4+-3i+-27i^2=0

Solution for 4+-3i+-27i^2=0 equation:

4+-3i+-27i^2=0

We add all the numbers together, and all the variables

-27i^2-3i=0

a = -27; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·(-27)·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*-27}=\frac{0}{-54}
=0
$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*-27}=\frac{6}{-54}
=-1/9
$